std::accumulate

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算法库
功能
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Functions
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修改序列操作
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Non-modifying sequence operations
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all_of
any_of
none_of
(C++11)
(C++11)
(C++11)
for_each
count
count_if
mismatch
equal
修改序列操作
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Modifying sequence operations
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分区操作
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Partitioning operations
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is_partitioned(C++11)
partition
partition_copy(C++11)
排序操作(排序的区间)
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Sorting operations (on sorted ranges)
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is_sorted(C++11)
is_sorted_until(C++11)
sort
二进制搜索操作(排序的区间)
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Binary search operations (on sorted ranges)
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设置操作(排序的区间)
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Set operations (on sorted ranges)
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堆的操作
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Heap operations
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最小/最大操作
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Minimum/maximum operations
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数字操作
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Numeric operations
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iota(C++11)
accumulate
inner_product
C库
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C library
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Defined in header <numeric>
template< class InputIt, class T >
T accumulate( InputIt first, InputIt last, T init );
(1)
template< class InputIt, class T, class BinaryOperation >

T accumulate( InputIt first, InputIt last, T init,

              BinaryOperation op );
(2)

Computes the sum of the given value init and the elements in the range [first, last). The first version uses operator+ to sum up the elements, the second version uses the given binary function op.

目录

[编辑] 参数

first, last -
元素的范围总和
Original:
the range of elements to sum
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init - initial value of the sum
op - binary operation function object that will be applied.

The signature of the function should be equivalent to the following:

Ret fun(const Type1 &a, const Type2 &b);

The signature does not need to have const &.
The type  Type1 must be such that an object of type T can be implicitly converted to  Type1. The type  Type2 must be such that an object of type InputIt can be dereferenced and then implicitly converted to  Type2. The type  Ret must be such that an object of type T can be assigned a value of type  Ret. ​

Type requirements
-
InputIt must meet the requirements of InputIterator.
-
T must meet the requirements of CopyAssignable and CopyConstructible.

[编辑] 返回值

The sum of the given value and elements in the given range.

[编辑] 可能的实现

First version
template<class InputIt, class T>
T accumulate(InputIt first, InputIt last, T value)
{
    for (; first != last; ++first) {
        value = value + *first;
    }
    return value;
}
Second version
template<class InputIt, class T, class BinaryOperation>
T accumulate(InputIt first, InputIt last, T value, 
             BinaryOperation op)
{
    for (; first != last; ++first) {
        value = op(value, *first);
    }
    return value;
}

[编辑] 为例

#include <iostream>
#include <vector>
#include <numeric>
#include <string>
 
int multiply(int x, int y)
{
    return x*y;
}
 
std::string magic_function(std::string res, int x)
{
    return res += (x > 5) ? "b" : "s";
}
 
int main()
{
    std::vector<int> v{1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
 
    int sum = std::accumulate(v.begin(), v.end(), 0);
    int product = std::accumulate(v.begin(), v.end(), 1, multiply);
    std::string magic = std::accumulate(v.begin(), v.end(), std::string(), 
                                        magic_function);
 
    std::cout << sum << '\n'
              << product << '\n'
              << magic << '\n';
}

Output:

55
3628800
sssssbbbbb

[编辑] 另请参阅

计算的范围内的相邻元件之间的差异
Original:
computes the differences between adjacent elements in a range
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(函数模板) [edit]
计算的内积的2的范围内的元素
Original:
computes the inner product of two ranges of elements
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(函数模板) [edit]
计算的部分和一定范围的元素
Original:
computes the partial sum of a range of elements
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(函数模板) [edit]