std::inplace_merge
来自cppreference.com
|
|
This page has been machine-translated from the English version of the wiki using Google Translate.
The translation may contain errors and awkward wording. Hover over text to see the original version. You can help to fix errors and improve the translation. For instructions click here. |
| Defined in header <algorithm>
|
||
| template< class BidirIt > void inplace_merge( BidirIt first, BidirIt middle, BidirIt last ); |
(1) | |
| template< class BidirIt, class Compare> void inplace_merge( BidirIt first, BidirIt middle, BidirIt last, Compare comp ); |
(2) | |
合并两个连续的排序的范围
[first, middle),[middle, last)成一个排序的范围[first, last)。保证保留相等元素的顺序。 operator<的第一个版本使用比较的元素,第二个版本使用给定的比较函数comp.Original:
Merges two consecutive sorted ranges
[first, middle) and [middle, last) into one sorted range [first, last). The order of equal elements is guaranteed to be preserved. The first version uses operator< to compare the elements, the second version uses the given comparison function comp.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
目录 |
[编辑] 参数
| first | - | 排序的第一范围的开头
Original: the beginning of the first sorted range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
| middle | - | 排序的第一范围的结束和开始的第二个
Original: the end of the first sorted range and the beginning of the second The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
| last | - | 结束所述第二排序条件范围
Original: the end of the second sorted range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
| comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. | |||||||||
| Type requirements | |||||||||||
-BidirIt must meet the requirements of ValueSwappable and BidirectionalIterator.
| |||||||||||
-The type of dereferenced BidirIt must meet the requirements of MoveAssignable and MoveConstructible.
| |||||||||||
[编辑] 返回值
(无)
Original:
(none)
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[编辑] 复杂性
究竟N-1比较,如果有足够的额外内存,否则N·log(N)其中N = std::distance(first, last).
Original:
Exactly N-1 comparisons if enough additional memory is available, otherwise N·log(N) where N = std::distance(first, last).
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[编辑] 注释
该函数尝试分配一个临时缓冲区,通常是通过调用std::get_temporary_buffer。如果分配失败,效率低的算法选择.
Original:
This function attempts to allocate a temporary buffer, typically by calling std::get_temporary_buffer. If the allocation fails, the less efficient algorithm is chosen.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[编辑] 为例
下面的代码是一个实现归并排序.
Original:
The following code is an implementation of merge sort.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
#include <vector> #include <iostream> #include <algorithm> template<class Iter> void merge_sort(Iter first, Iter last) { if (last - first > 1) { Iter middle = first + (last - first) / 2; merge_sort(first, middle); merge_sort(middle, last); std::inplace_merge(first, middle, last); } } int main() { std::vector<int> v{8, 2, -2, 0, 11, 11, 1, 7, 3}; merge_sort(v.begin(), v.end()); for(auto n : v) { std::cout << n << ' '; } std::cout << '\n'; }
Output:
-2 0 1 2 3 7 8 11 11
[编辑] 另请参阅
| 合并两个已排序的范围 Original: merges two sorted ranges The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (函数模板) | |
| 为升序排序范围 Original: sorts a range into ascending order The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (函数模板) | |
| 排序范围内的元素,同时保持相等的元素之间的顺序 Original: sorts a range of elements while preserving order between equal elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (函数模板) | |