std::recursive_timed_mutex::lock
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< cpp | thread | recursive timed mutex
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| void lock(); |
(C++11 起) | |
锁定互斥锁。如果另一个线程已经锁定了互斥体,调用
lock将阻止执行,直到锁被收购.Original:
Locks the mutex. If another thread has already locked the mutex, a call to
lock will block execution until the lock is acquired.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
A thread may call lock on a recursive mutex repeatedly. Ownership will only be released after the thread makes a matching number of calls to unlock.
The maximum number of levels of ownership is unspecified. An exception of type std::system_error will be thrown if this number is exceeded.
目录 |
[编辑] 参数
(无)
Original:
(none)
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[编辑] 返回值
(无)
Original:
(none)
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[编辑] 例外
抛出std::system_error当错误发生时,包括从底层的操作系统,防止错误
lock满足其规格.Original:
Throws std::system_error when errors occur, including errors from the underlying operating system that would prevent
lock from meeting its specifications.The text has been machine-translated via Google Translate.
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[编辑] 为例
此示例显示了如何
lock和unlock可用于保护共享数据.
Original:
This example shows how
lock and unlock can be used to protect shared data.
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#include <iostream> #include <chrono> #include <thread> #include <mutex> int g_num = 0; // protected by g_num_mutex std::mutex g_num_mutex; void slow_increment(int id) { for (int i = 0; i < 3; ++i) { g_num_mutex.lock(); ++g_num; std::cout << id << " => " << g_num << '\n'; g_num_mutex.unlock(); std::this_thread::sleep_for(std::chrono::seconds(1)); } } int main() { std::thread t1(slow_increment, 0); std::thread t2(slow_increment, 1); t1.join(); t2.join(); }
Possible output:
0 => 1 1 => 2 0 => 3 1 => 4 0 => 5 1 => 6
[编辑] 另请参阅
| 试图锁定互斥锁,则返回,如果该互斥锁不可用 Original: tries to lock the mutex, returns if the mutex is not available The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (公共成员函数) | |
| 试图锁定互斥锁,则返回在指定的超时时间,如果互斥体有been unavailable的 Original: tries to lock the mutex, returns if the mutex has been unavailable for the specified timeout duration The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (公共成员函数) | |
| 试图锁定互斥锁,返回到指定的时间点已经达到,如果互斥been unavailable的 Original: tries to lock the mutex, returns if the mutex has been unavailable until specified time point has been reached The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (公共成员函数) | |
| 互斥量被释放 Original: unlocks the mutex The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (公共成员函数) | |