std::has_virtual_destructor
来自cppreference.com
|
|
This page has been machine-translated from the English version of the wiki using Google Translate.
The translation may contain errors and awkward wording. Hover over text to see the original version. You can help to fix errors and improve the translation. For instructions click here. |
| Defined in header <type_traits>
|
||
| template< class T > struct has_virtual_destructor; |
(C++11 起) | |
如果
T是一种虚析构函数,成员常量valuetrue平等。对于任何其他类型,value是false.Original:
If
T is a type with a virtual destructor, provides the member constant value equal true. For any other type, value is false.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
目录 |
Inherited from std::integral_constant
Member constants
| value [静态的] </ SPAN></div></div>
|
true如果 T has a virtual destructor ,false其他方式 Original: true if T has a virtual destructor , false otherwise The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (公共静态成员常量) |
Member functions
| operator bool |
转换的对象bool,返回 value Original: converts the object to bool, returns value The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (公共成员函数) |
Member types
| 类型
Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
value_type
|
bool
|
type
|
std::integral_constant<bool, value> |
</div>
[编辑] 注释
如果一个类有一个公有虚析构函数,它可以派生,派生类对象可以通过指针被安全地删除的基本对象(C++FAQ Lite 20.7)
Original:
If a class has a public virtual destructor, it can be derived from, and the derived object can be safely deleted through a pointer to the base object (C++FAQ Lite 20.7)
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[编辑] 为例
#include <iostream> #include <type_traits> #include <string> #include <stdexcept> int main() { std::cout << std::boolalpha << "std::string has a virtual destructor? " << std::has_virtual_destructor<std::string>::value << '\n' << "std::runtime_error has a virtual destructor? " << std::has_virtual_destructor<std::runtime_error>::value << '\n'; }
Output:
std::string has a virtual destructor? false std::runtime_error has a virtual destructor? true
[编辑] 另请参阅
| (C++11) (C++11) (C++11) |
如果一个类型的检查,具有不可删除的析构函数 Original: checks if a type has a non-deleted destructor The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (类模板) |