std::remove_pointer
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| Defined in header <type_traits>
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| template< class T > struct remove_pointer; |
(C++11 起) | |
Provides the member typedef type which is the type pointed to by T, or, if T is not a pointer, then type is the same as T.
目录 |
[编辑] 会员类型
| 姓名
Original: Name The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
type
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the type pointed to by T or T if it's not a pointer
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[编辑] 可能的实现
template< class T > struct remove_pointer {typedef T type;}; template< class T > struct remove_pointer<T*> {typedef T type;}; template< class T > struct remove_pointer<T* const> {typedef T type;}; template< class T > struct remove_pointer<T* volatile> {typedef T type;}; template< class T > struct remove_pointer<T* const volatile> {typedef T type;}; |
[编辑] 为例
| 本节是不完整的 原因: no example |
[编辑] 另请参阅
| (C++11) |
检查如果一个类型是一个指针类型 Original: checks if a type is a pointer type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (类模板) |
| (C++11) |
添加到给定的类型的指针 Original: adds pointer to the given type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (类模板) |