std::minus
来自cppreference.com
< cpp | utility | functional
|
|
This page has been machine-translated from the English version of the wiki using Google Translate.
The translation may contain errors and awkward wording. Hover over text to see the original version. You can help to fix errors and improve the translation. For instructions click here. |
| Defined in header <functional>
|
||
| template< class T > struct minus; |
||
执行减法的函数对象。有效地调用operator-的两个实例的类型
T.Original:
Function object for performing subtraction. Effectively calls operator- on two instances of type
T.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
目录 |
[编辑] 会员类型
| 类型
Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
result_type
|
T
|
first_argument_type
|
T
|
second_argument_type
|
T
|
[编辑] 成员函数
| operator() |
返回两个参数之间的差异 Original: returns the difference between two arguments The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (公共成员函数) |
的std ::负Original:std::minus::The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.operator()
Original:
std::minus::
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
| T operator()( const T& lhs, const T& rhs ) const; |
||
Returns the difference between lhs and rhs.
Parameters
| lhs, rhs | - | 值减去从彼此
Original: values to subtract from one another The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Return value
The result of lhs - rhs.
Exceptions
(none)
Possible implementation
T operator()(const T &lhs, const T &rhs) const { return lhs - rhs; } |