std::modulus
来自cppreference.com
< cpp | utility | functional
|
|
This page has been machine-translated from the English version of the wiki using Google Translate.
The translation may contain errors and awkward wording. Hover over text to see the original version. You can help to fix errors and improve the translation. For instructions click here. |
| Defined in header <functional>
|
||
| template< class T > struct modulus; |
||
部門計算餘下的函數對象。實現operator%類型
T.Original:
Function object for computing remainders of divisions. Implements operator% for type
T.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
目錄 |
[编辑] 會員類型
| 類型
Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
result_type
|
T
|
first_argument_type
|
T
|
second_argument_type
|
T
|
[编辑] 成員函數
| operator() |
其餘的劃分第一個參數的第二個參數返回 Original: returns the remainder from the division of the first argument by the second argument The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (公共成員函數) |
的std ::模量Original:std::modulus::The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.operator()
Original:
std::modulus::
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
| T operator()( const T& lhs, const T& rhs ) const; |
||
Returns the remainder of the division of lhs by rhs.
Parameters
| lhs, rhs | - | 劃分一個值
Original: values to divide one by another The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Return value
The result of lhs % rhs.
Exceptions
(none)
Possible implementation
T operator()(const T &lhs, const T &rhs) const { return lhs % rhs; } |